V\u00ed d\u1ee5:<\/strong><\/p>\n+) S\u1ed1 75 s\u1ebd c\u00f3 t\u1ed5ng b\u1eb1ng 7 + 5 = 12<\/p>\n
Theo ph\u01b0\u01a1ng ph\u00e1p t\u00ednh \u0111i\u1ec3m trong n\u1ed9i dung n\u00e0y l\u00e0 \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 th\u00ec 75 n\u1eb1m trong d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 do 7 + 5 = 12 l\u1edbn h\u01a1n 10.<\/p>\n
+) S\u1ed1 23 s\u1ebd c\u00f3 t\u1ed5ng b\u1eb1ng 2 + 3 = 5<\/p>\n
Theo ph\u01b0\u01a1ng ph\u00e1p c\u1ee7a b\u00e0i n\u00e0y th\u00ec 23 \u0111\u01b0\u1ee3c s\u1eafp v\u00e0o d\u00e0n \u0111\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10 b\u1edfi v\u00ec 2 + 3 = 5 nh\u1ecf h\u01a1n 10. Sau khi xem 2 v\u00ed d\u1ee5 tr\u00ean ch\u1eafc h\u1eb3n anh em \u0111\u00e3 hi\u1ec3u v\u1ec1 ph\u01b0\u01a1ng ph\u00e1p ph\u00e2n lo\u1ea1i d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 hay d\u00e0n \u0111\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10 c\u1ee7a kubet r\u1ed3i ph\u1ea3i kh\u00f4ng. V\u1eady d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 c\u00f3 bao nhi\u00eau con? T\u1ed5ng d\u01b0\u1edbi 10 c\u00f3 bao nhi\u00eau con? \u0110\u00f3 l\u00e0 nh\u1eefng con s\u1ed1 n\u00e0o? H\u00e3y theo d\u00f5i ph\u1ea7n ti\u1ebfp theo c\u1ee7a b\u00e0i vi\u1ebft n\u00e0y nh\u00e9.<\/p>\n
D\u00e0n \u0111\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10 c\u00f3 bao nhi\u00eau con<\/h3>\n
\u0110\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10 theo nh\u01b0 \u0111\u1ecbnh ngh\u0129a \u1edf tr\u00ean s\u1ebd c\u00f3 55 s\u1ed1 v\u1edbi t\u1ed5ng 2 ch\u1eef s\u1ed1 b\u00e9 h\u01a1n 10. D\u00e0n \u0111\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10 s\u1ebd bao g\u1ed3m c\u00e1c con s\u1ed1 d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n
00 \u2013 01 \u2013 02 \u2013 03 \u2013 04 \u2013 05 \u2013 06 \u2013 07 \u2013 08 \u2013 09<\/p>\n
10 \u2013 11 \u2013 12 \u2013 13 \u2013 14 \u2013 15 \u2013 16 \u2013 17 \u2013 18<\/p>\n
20 \u2013 21 \u2013 22 \u2013 23 \u2013 24 \u2013 25 \u2013 26 \u2013 27<\/p>\n
30 \u2013 31 \u2013 32 \u2013 33 \u2013 34 \u2013 35 \u2013 36<\/p>\n
40 \u2013 41 \u2013 42 \u2013 43 \u2013 44 \u2013 45<\/p>\n
50 \u2013 51 \u2013 52 \u2013 53 \u2013 54<\/p>\n
60 \u2013 61 \u2013 62 \u2013 63<\/p>\n
70 \u2013 71 \u2013 72<\/p>\n
80 \u2013 81<\/p>\n
90<\/p>\n
Ti\u1ebfp \u0111\u1ebfn h\u00e3y c\u00f9ng t\u00ecm hi\u1ec3u d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 g\u1ed3m nh\u1eefng s\u1ed1 n\u00e0o nh\u00e9.<\/p>\n
D\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 g\u1ed3m bao nhi\u00eau con<\/h3>\n
Do d\u00e0n \u0111\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10 s\u1ebd c\u00f3 55 con v\u00ec v\u1eady 45 con s\u1ed1 c\u00f2n l\u1ea1i s\u1ebd n\u1eb1m trong d\u00e0n \u0111\u1ec1 t\u1ed5ng l\u1edbn h\u01a1n 10. D\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 bao g\u1ed3m nh\u1eefng con s\u1ed1 d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n
19<\/p>\n
28 \u2013 29<\/p>\n
37 \u2013 38 \u2013 39<\/p>\n
46 \u2013 47 \u2013 48 \u2013 49<\/p>\n
55 \u2013 56 \u2013 57 \u2013 58 \u2013 59<\/p>\n
64 \u2013 65 \u2013 66 \u2013 67 \u2013 68 \u2013 69<\/p>\n
73 \u2013 74 \u2013 75 \u2013 76 \u2013 77 \u2013 78 \u2013 79<\/p>\n
82 \u2013 83 \u2013 84 \u2013 85 \u2013 86 \u2013 87 \u2013 88 \u2013 89<\/p>\n
91 \u2013 92 \u2013 93 \u2013 94 \u2013 95 \u2013 96 \u2013 97 \u2013 98 \u2013 99<\/p>\n
B\u00ean c\u1ea1nh \u0111\u00f3 m\u1ed9t s\u1ed1 bi\u1ebfn th\u1ec3 kh\u00e1c s\u1ebd kh\u00f4ng t\u00ednh nh\u1eefng s\u1ed1 c\u00f3 t\u1ed5ng b\u1eb1ng 10 v\u00e0o trong d\u00e0n \u0111\u1ec1 t\u1ed5ng l\u1edbn h\u01a1n 10. Tr\u01b0\u1eddng h\u1ee3p kh\u00f4ng t\u00ednh nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 b\u1eb1ng 10 th\u00ec d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 s\u1ebd c\u00f3 nh\u1eefng con s\u1ed1 sau \u0111\u00e2y:<\/p>\n
<\/p>\n
29<\/p>\n
38 \u2013 39<\/p>\n
47 \u2013 48 \u2013 49<\/p>\n
56 \u2013 57 \u2013 58 \u2013 59<\/p>\n
65 \u2013 66 \u2013 67 \u2013 68 \u2013 69<\/p>\n
74 \u2013 75 \u2013 76 \u2013 77 \u2013 78 \u2013 79<\/p>\n
83 \u2013 84 \u2013 85 \u2013 86 \u2013 87 \u2013 88 \u2013 89<\/p>\n
92 \u2013 93 \u2013 94 \u2013 95 \u2013 96 \u2013 97 \u2013 98 \u2013 99<\/p>\n
Nh\u01b0 v\u1eady theo c\u00e1ch t\u00ednh n\u00e0y th\u00ec d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 s\u1ebd ch\u1ec9 c\u00f3 36 con s\u1ed1 nh\u01b0 tr\u00ean.<\/p>\n
Qua n\u1ed9i dung n\u00e0y ch\u1eafc h\u1eb3n anh em c\u0169ng \u0111\u00e3 hi\u1ec3u r\u00f5 v\u1ec1 d\u00e0n \u0111\u1ec1 t\u1ed5ng tr\u00ean 10 v\u00e0 d\u00e0n \u0111\u1ec1 t\u1ed5ng d\u01b0\u1edbi 10. Hy v\u1ecdng n\u1ed9i dung n\u00e0y s\u1ebd h\u1ed7 tr\u1ee3 t\u1ed1i \u0111a \u0111\u01b0\u1ee3c cho anh em trong vi\u1ec7c soi c\u1ea7u khi \u0111\u00e1nh l\u00f4 \u0111\u1ec1 online. \u0110\u1ec3 t\u00ecm hi\u1ec3u th\u00eam nhi\u1ec1u kinh nghi\u1ec7m c\u0169ng nh\u01b0 d\u00e0n \u0111\u1ec1 kh\u00e1c c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 tham kh\u1ea3o t\u1ea1i \u0111\u00e2y. Ch\u00fac anh em lu\u00f4n m\u1ea1nh kh\u1ecfe v\u00e0 th\u00e0nh c\u00f4ng!<\/p>\n
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